CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
Saurabh SIngh

· started a discussion

· 1 Months ago

nice (Question: 111074.0 )

good question

Question:

Adjoining are three circles, each of radius 20 and centres at P, Q and R; further

AB = 5, CD = 10 and EF = 12. What is the perimeter of  the triangle PQR?


Options:
A) 120
B) 66
C) 93
D) 87
Solution:
Ans: (c)

Since AB = 5, PA = PB - AB = 20 - 5 = 15

Similarly  RB = RA - AB = 20 - 5 = 15

Hence PR = PA + AB + BR = 15 + 5 + 15 = 35

Since CD = 10, RC = RD - DC = 20 - 10 = 10

Similarly QD = QC - DC = 20 - 10 = 10

Hence QR = RC + CD + DQ = 10 + 10 + 10 = 30

And since EF = 12, PF = PE - EF = 20 - 12 = 8

and EQ = QF - EF = 20 - 12 = 8

Hence, PQ = PF + EF + EQ = 8 + 12 + 8 = 28

Hence, perimeter of triangle  PQR = 35 + 30 + 28 = 93

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Thanks for your support.
Keep learning with us.

Thanks and Regards
Team TR
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions