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harshit

· started a discussion

· 1 Months ago

nice appraoch. (Question: 113235.0 )

gud .

Question:

If the compound interest on a certain sum for 2 years at 3% be Rs. 101.50, What would be the S.I.?

Options:
A) Rs 110
B) Rs 120
C) Rs 100
D) Rs 90
Solution:
Ans: (c)
C.I. on 1 rupee =\(\left (1+\cfrac{3}{100} \right )^2\ \ -\ 1=\left (\cfrac{103}{100} \right )^2\ \ -\ 1\) = Rs. \(\cfrac{609}{10000}\)

S.I. on 1 rupee = \(\cfrac{2×3}{100}\)  = Rs. \(\cfrac{6}{100}\)

\(\therefore\)\(\cfrac{S.I.}{C.I.} =\cfrac{6}{100} × \cfrac{10000}{609}=\cfrac{200}{203}\).

S.I. = \(\cfrac{200}{203}\) of C.I. = \(\cfrac{200}{203}×101.5\) = Rs. 100

Knowledge Expert

· commented

· 1 Months ago

Thank you.
Keep learning,
Team TR

ABHIJITH P M

· commented

· 1 Months ago

for two years CI = SI (1+R/200)
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