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Suresh Kumar

· started a discussion

· 1 Months ago

need solution (Question: 336987.0 )

u need to provide the solution to the aspirants its pretty wrong to just give answers

Question:

Find the sum of squares of the median MP and OQ drawn in right angled triangle MNO. The longest side of MNO is 20 cm.

  

Options:
A)

200

B)

300

C)

400

D)

500

Solution:

Ans: (d)


Knowledge Expert

· commented

· 1 Months ago

as QC is a median it will bisect MN in 2 equal parts
i.e. MQ=QN=a
as MP is a median on NO, it will bisect NO in two equal parts
i.e. NP=NO=b
1. Considering Triangle MNO
mo^2=mn^2+no^2
400=(2a)^2+(2b)^2
a^2+b^2=10^2
So, the possible value of a and b are (6,8) or (8,6)
Taking a=8 and b=6
Now, Taking triangle MPN
MP^2=NP^2+MN^2
MP^2=(16)^2+(6)^2
MP^2=292...............(1)
nOW, taking triangle QNO,
QO^2=QN^2+NO^2
QO^2=(8)^2+(12)^2
QO^2=208.................(2)
nOW, ADDING (1) AND (2)
=500

ketan gupta

· commented

· 1 Months ago

exactly
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