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Munagala Janardhana Reddy

· started a discussion

· 1 Months ago

my solution (Question: 246945.0 )

let large square(S1) side=2x
let small square(S2) side=root(2)*x
radius of circle (R)=(1/2)*root(2)*x ==> R=x/root(2)
we know that circumradius (R) =a/root(3)

a/root(3) = x/root(2) ==> a = x*root(3/2)

given 2x=4 ==> x=4;
Area of equilateral triangle =root(3) /4 *a^2 =6*root(3).

Question:
Find the area of the equilateral triangle inscribed in a circle circumscribed by a square made by joining the mid points of the adjacent sides of a square of side 8 cm. 
Options:
A) 12 cm2
B) \(12\sqrt{3}\) cm2
C) \(47(\pi-12)\) cm2
D) \(6\sqrt{3}\) cm2
Solution:
Ans: (d)


Knowledge Expert

· commented

· 1 Months ago

Dear student,

YES this one also an another way to solve this question.. Good keep it up.

Best wishes
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