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Munagala Janardhana Reddy

· started a discussion

· 1 Months ago

my solution (Question: 109859.0 )

let father and son age 5 years ago from present be ( F , S) ==>F = 3-->eq1
let father and son age 5 years hence from present be ( F+ 10 , S + 10)

==> (F+10) /(S+10) =11/5 -->eq2
ie present age of father is (F +5)
ie present age of son is(S+5)
from eq1 in eq2 we get F = 45
ie present age of father in (F +5) =50

Question:
5 year ago, the father’s age was 3 times of his son’s age. 5 years hence the ratio between the ages of the father and the son will become 11: 5. Find the father’s present age.
Options:
A) 40 years
B) 45 years
C) 50 years
D) 55 years
Solution:
Ans(c) 


Let the 5 years ago, father's age and son's age was 3x and x respectively.


5 year later, Fathers age=3x+5+5=3x+10

and his son age =x+5+5=x+10


According to question,


\(\cfrac{3x+10}{x+10}=\cfrac{11}{5}\)

15x+50=11x+110

4x=60

x=60/4

x=15


Father's present age=3x+5=3x15+5=45+5=50 years

Knowledge Expert

· commented

· 1 Months ago

ok,
Keep learning,
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