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Munfaij Khan

· started a discussion

· 1 Months ago

munfaij khan (Question: 99450.0 )

galat sol.,sure you can check ....shed is rectangular not square so.......radius will be =r1=10....and r2=13..............check it top ranker and realize your mistake

Question:
A cow is tied to one corner of a closed shed located in a field. The length and width of the shed are 15 m × 15 m and the length of the rope that is used to tie the cow is 25 m. What is the area in which the cow can graze?
Options:
A) \(478.75π sq. m\)
B) \(542.25 π sq. m\)
C) \(518.75π sq. m\)
D) \(604.25 π sq. m\)
Solution:
Ans: (c)



The area that can be grazed by the cow is the sum of the areas of the regions A, B, C. 
∴ Total area that can be grazed
\(=\cfrac{270}{360}× π(25)^2 + 2\left ( \cfrac {90}{360}×π(10)^2 \right )=\cfrac{π}{4}(3 × 625 + 2 × 100)\)
\(=\cfrac{2075π}{4}= 518.75 π\)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

we fixed its ambiguity of this question.

Best wishes
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