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himanshu singh

· started a discussion

· 1 Months ago

mind it (Question: 246548.0 )

min value of function is -4 at x=0, so question should be At which point value of f(x) is minimum

Question:
Find the minimum value of f(x) = \(x^2+\cfrac{1}{x^2-1}-3\)
Options:
A) 1
B) 0
C) 2
D) 3
Solution:

Ans: (b)


Gurdeep Kaur

· commented

· 1 Months ago

but this is not in the options, so what should be done?
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