may be this is the solution (Question: 292693.0 )

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jishnu r

· started a discussion

· 1 Months ago

may be this is the solution (Question: 292693.0 )

A tan(x+150)=B tan(60-x)

A tan(90+x+60)=B tan(60-x)

A -cot(x+60)=B tan(60-x)

-A /tan(x+60)=B tan(60-x)

-A /B*tan(60)= tan(60-x)tan(x+60)tan(60)

-A /B*tan(60)=tan180=0 hence A =0

A -B/A +B=-B /B=-1

Question:

If A × tan(θ + 150º) = B × tan(θ – 60º), then $\frac{A - B}{A + B}$ equals to –

Options:

$\frac{\sin 2 q}{2}$

$\frac{\cos 2 q}{2}$

tan 2 θ

Solution:

Ans: (d)

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may be this is the solution (Question: 292693.0 )

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