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PRANJUL MISHRA

· started a discussion

· 1 Months ago

maths (Question: 528739.0 )

provide solution

Question:

A mixture contains wine and water in the ratio 3 : 2 and another mixture contains them in the ratio 4 : 5. How many litres of the latter must be mixed with 3 litres of the farmer so that the resultant mixture may contain equal quantity of wine and water?

Options:
A)

275    

B)

225    

C)

256    

D)

285    

Solution:

 Ans: (a)

Solution A ⇒ 3 litres solution (3 : 2 ∷ wine : water)
Solution B ⇒ x litres solution (4 : 5 ∷ wine : water)
According to question Solution A is mixed with Solution B and forms
⇒ (3 + x) litres solution (1 : 1 ∷ wine : water)
For Wine
Wine in Sol A + Wine in Sol B = Wine in net Solution

(3/5) × 3 + (4/9) × x = 1/2 × (3+x)

⇒ (4x/9) – (x/2) = (3/2) - (9/5)

⇒ (8x/18) – (9x/18) = (15/10) – (18/10)

⇒ 3/10 = x / 18

⇒ x = 27/5 litres

Knowledge Expert

· commented

· 1 Months ago

Dear student
We have updated the solution .

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