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Saptarshi Sadhu

· started a discussion

· 1 Months ago

Math 14 (Question:163004.0)

Corret the given option

Question:
If X = 2 + \(\sqrt{2}\) + \(\sqrt{9}\), then find the value of  X² – 4x + 9.
Options:
A) 2[6 + \(\sqrt{12}\)]
B) 12 + \(\sqrt{12}\)
C) 16 + 6\(\sqrt{2}\)
D) 18 + 3\(\sqrt{2}\)  
Solution:

Ans: (c) X = 2 + √2 + √9

(x – 2)²  = [√2 + √9 ]²

X² – 4x + 4    = 2 + 9 + 2\(\sqrt{18}\)

X² – 4x + 4 + 5  = 2 + 9 + 2\(\sqrt{18}\) + 5

X² – 4x + 9    = 16 + 6\(\sqrt{2}\)

Knowledge Expert

· commented

· 1 Months ago

Dear student
We have fixed it.

Keep learning
Team TR

Knowledge Expert

· commented

· 1 Months ago

Yet to be approved!
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