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Sohil Rajput

· started a discussion

· 1 Months ago

le bhai solution tu bhi kya yaad rakhega (Question: 364656.0 )

Let x be the length of the course

A beats B by 15 metres and C by 29 metres

=> When A runs x metre, B runs (x-15) metre and C runs (x-29) metre

When B and C run over the course together, B wins by 15 metres

=> when B runs x metre, C run (x-15) metre

=> when B runs 1 metre, C run x−15x metre=> when B runs (x-15) metre, C run x−15x×(x−15)=(x−15)2x metrei.e., (x−29)=(x−15)2x⇒x2−29x=x2−30x+225⇒−29x=−30x+225⇒x=225

Question:

In a race, A beats B by 15 metres and C by 29 metres. When B and C run over the course together, B wins by 15 metres. Find the length of the course. 

Options:
A)

225 m

B)

125 m

C)

220 m

D)

256 m

Solution:

Ans:(a) 


Jitendra Kumawat

· commented

· 1 Months ago

Thnx bhai 🙏🙏

salim khan

· commented

· 1 Months ago

Yet to be approved!

Vikas Singh

· commented

· 1 Months ago

a b c


x x-15 x-29


x x-15


now x/(x-15)=(x-15)/(x-29) x=225

Gambhir Chauhan

· commented

· 1 Months ago

Bhai smjh me ni aaya
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