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Keshav Singh

· started a discussion

· 1 Months ago

last term (Question: 222759.0 )

ye kese pta chlega ki last term 19*21 bnegi

Question:
The value of the expression \(\left ( \cfrac {1}{2^2 - 1} \right )\) + \(\left ( \cfrac {1}{4^2 - 1} \right ) + \left ( \cfrac {1}{6^2 - 1} \right ) \) + ...........+ \(\left ( \cfrac {1}{20^2 - 1} \right )\) is equal to -
Options:
A) \(\cfrac{9}{19}\)
B) \(\cfrac{10}{19}\)
C) \(\cfrac{10}{21}\)
D) \(\cfrac{11}{21}\)
Solution:
Ans: (c)


SOUMYA MAJUMDER

· commented

· 1 Months ago

a^2-b^2=(a+b)(a-b)

Gaurav Saini

· commented

· 1 Months ago

i am also at sea how to find last term.is qes me to fir b pta chal jayega lekin jyada lambi term me muskil ho jata h
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