koi aur method? (Question:327715.0)

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Dushyant Kaushik

· started a discussion

· 1 Months ago

koi aur method? (Question:327715.0)

kisi ka koi aur method h toh btana

Question:

If $s i n α s i n β - c o s α c o s β + 1 = 0$ then the value $c o t α t a n β$ of

Options:

-1

None of these

Solution:

$\begin{matrix} s i n α s i n β - c o s α c o s β + 1 = 0 \\ c o s (α + β) = 1 \\ α + β = 0^{0} \\ S o s i n (α + β) = 0 \\ \Rightarrow s i n α c o s β + c o s α s i n β = 0 \\ \Rightarrow s i n α c o s β + c o s α s i n β = 0 \\ \Rightarrow s i n α c o s β = - c o s α s i n β \\ \Rightarrow \frac{s i n α c o s β}{c o s α s i n β} = - 1 \\ \Rightarrow c o t β t a n α = - 1 \\ \Rightarrow c o t α t a n β = (- 1) \end{matrix}$ α+β$)$=1α+β=00So sin$($α+β$)$=0⇒sinαcosβ+cosαsinβ=0⇒sinαcosβ+cosαsinβ=0⇒sinαcosβ=−cosαsinβ⇒sinαcosβcosαsinβ=−1⇒cotβtanα=−1⇒cotαtanβ=(−1)sinαsinβ−cosαcosβ+1=0cos(α+β)=1α+β=00So sin(α+β)=0⇒sinαcosβ+cosαsinβ=0⇒sinαcosβ+cosαsinβ=0⇒sinαcosβ=−cosαsinβ⇒sinαcosβcosαsinβ=−1⇒cotβtanα=−1⇒cotαtanβ=(−1) $\begin{matrix} s i n α s i n β - c o s α c o s β + 1 = 0 \\ c o s (α + β) = 1 \\ α + β = 0^{0} \\ S o s i n (α + β) = 0 \\ \Rightarrow s i n α c o s β + c o s α s i n β = 0 \\ \Rightarrow s i n α c o s β + c o s α s i n β = 0 \\ \Rightarrow s i n α c o s β = - c o s α s i n β \\ \Rightarrow \frac{s i n α c o s β}{c o s α s i n β} = - 1 \\ \Rightarrow c o t β t a n α = - 1 \\ \Rightarrow c o t α t a n β = (- 1) \end{matrix}$

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koi aur method? (Question:327715.0)

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