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Dushyant Singh Shekhawat

· started a discussion

· 1 Months ago

Kindly learn to write question properly. Dont be so careless. (Question: 224128.0 )

In question you have written (b^2 - 1^2)

Whereas in solution you have written (b^2 - 1^2)^2

Question:
If tan\(\theta\) - cot\(\theta\) =a and cos\(\theta\) + sin\(\theta\) = b, then (b2 - 12) (a2 + 4) = ? 
Options:
A) 1
B) 4
C) 2
D) 0
Solution:
Ans: (b)


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