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Knowledge Expert
· commented
· 1 Months ago
x/a = (b-c)_________(1)
y = b (c – a)
y/b=(c-a)__________(2)
z = c (a – b)
z/c=(a-b)___________(3)
Add (1),(2) and (3),
x/a + y/b + z/c = 0
Since, α^3+β^3+¥^3-3αβ¥=0 if α+β+¥=0
Take α=x/a, β=y/b and ¥=z/c
Now, simply put the value of α,β and ¥ in the given equation:
α^3+β^3+¥^3=3αβ¥