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D.RAJ

· started a discussion

· 1 Months ago

kindly Correct the answer (Question: 192465.0 )

A cyclic quadrilateral is a quadrilateral whose vertices all touch the circumference of a circle. The opposite angles add up to 180o.
Inscribed angles subtended by a diameter are right.
Since AOB is a diameter therefore Angle ACB is 90 degrees ,Now since ACB is a Triangle therefore it will make a sum of 180 degrees which implies ABC to be 55 degrees .
Since as mentioned opposite angles of a cyclic quadrilatral make an angle of 180 degrees therefore angle ADC+ angle ABC = 180 degrees and since we have calculated angle ABC to be 55 degrees thus Angle ADB will be 115 degrees

Question:
In the given figure, AOB is a diameter of the circle and CD || AB. If \(\angle \)CAB = 25°, then find the value of \(\angle \)CAD.


Options:
A) 45°
B) 40°
C) 65°
D) 115°
Solution:
Ans: (b)


Knowledge Expert

· commented

· 1 Months ago

Calculate CAD............not ADB

Knowledge Expert

· commented

· 1 Months ago

Please see the solution,

angle BCD + angle DAB = 180

25 + 90 +25 + angle CAD = 180

angle CAD = 40
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