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JATIN JAIN

· started a discussion

· 1 Months ago

jatin (Question: 187480.0 )

dont understand

Question:
Find the following sum of below terms.

\(\cfrac{1}{2^2-1}+\cfrac{1}{4^2-1}+\cfrac{1}{6^2-1}+.....+\cfrac{1}{20^2-1}\)

Options:
A) \(\cfrac{9}{10}\)
B) \(\cfrac{19}{21}\)
C) \(\cfrac{10}{11}\)
D) \(\cfrac{10}{21}\)
Solution:

Ans: (D)


Knowledge Expert

· commented

· 1 Months ago

Hi just apply the formula, a^2-b^2 =(a+b)(a-b)
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