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bablu chandora

· started a discussion

· 1 Months ago

issue (Question: 196508.0 )

option number [a] is also right

Question:
A number 476**0 is divisible by both 3 and 11. The digit in the hundred and tenth place respectively are (if digits are non-zero). 
Options:
A) 7, 4
B) 7, 5 
C) 8, 5
D) 4, 3
Solution:
Ans: (c)

(4 + 7 + 6 + x + y + 0) =17 + (x + y)

or,(x + 7) – (y + 6 + 4) = x – y – 3

Now, [17 + (x + y)] must be divisible by 3

and (x – y – 3) is either 0 or divisible by 11.

Clearly x = 8, y = 5 satisfy both the conditions.

RAJNEESH MEENA

· commented

· 1 Months ago

Yet to be approved!

manish kumar sagar

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himanshu singh

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Harkesh Lodhi

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ashish kr singh

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Mahesh kumar tiwari

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Bharatveer Malik

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kapil jadaun

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· 1 Months ago

Yet to be approved!
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