CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
NAVNEET

· started a discussion

· 1 Months ago

issue (Question: 111076.0 )

Experts why not clarify the issue

Question:
The point of intersection of three lines 2x+3y-5 = 0, 5x-7y+2 = 0 and 9x-5y-4 = 0:
Options:
A) form a triangle
B) are on lines perpendicular to each other
C) are on line parallel to each to other
D)  are coincident
Solution:
Ans: (d)

From eqn (1) and (2) we get,

(2x + 3y) = 5

5x - 7y = -2

elimination by equating the coefficient method

5(2x + 3y = 5)

2(5x - 7y = -2)

\(\Rightarrow\) 10x + 15y = 25

10x - 14y = -4

29y = 29

y = 1

and x = 1

Now put x = 1 and y = 1 eqn (3)

LHS = RHS

∴ Points are coincident

Vijay Sharma

· commented

· 1 Months ago

Knowledge expert toh khud chutiya nikla.... line ko coincident bata raha hai...bc points of intersection are co incident

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Equation of three lines is given find the value of X and Y... we get lines are coincident.

Best wishes
Team TR
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions