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Abhimanyu arya

· started a discussion

· 1 Months ago

is this correct (Question: 109964.0 )

A-15, efficiency-4
B-20,efficiency-3
C-30,efficiency-:(-2)
then
total work 60
total work in 3 min- 5
therefore total time=(60*3)/5=36min
Answer:D

Question:
Two pipes A and B can fill a cistern in 15 and 20 minutes respectively while third pipe C can empty the tank in 30 minutes. If the three taps are opened successively for one minute each, how long will it take to fill the cistern?
Options:
A) 34 minutes
B)  34\(\cfrac{1}{3}\) minutes
C) 35 minutes
D) 36 minutes
Solution:
Ans: (b) Work of three pipes for 3 minutes (one minute’s work of each pipe)

\(=\frac{1}{15}+\frac{1}{20}-\frac{1}{30}\)


\(\frac{4+3-2}{60}=\frac{5}{60}=\frac{1}{12}\)

\(\therefore\) Work of three pipes for 11 minutes each \(=\cfrac{1}{12}\times11=\cfrac{11}{12}\)

Total time = 11 × 3 = 33 minutes

\(\therefore\) Remaining part to be filled \(=1-\cfrac{11}{12}=\cfrac{1}{12}\)

Tap A will fill \(\cfrac{1}{15}\) of the cistern in the next 1 minutes.

\(\therefore\) Remaining portion to be filled by tap B \(=\cfrac{1}{12}-\cfrac{1}{15}=\cfrac{1}{60}\)

Time taken by tap B to fill \(\cfrac{1}{60}\) of the cistern \(=\cfrac{1}{60}\times 20=\cfrac{1}{3}\) minutes

\(\therefore\) Total time taken \(=33+1+\cfrac{1}{3}=34\cfrac{1}{3}\) minutes

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Given answer is correct.
Keep learning,
Team TR

Abhimanyu arya

· commented

· 1 Months ago

please reply ASAP!!
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