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Dipti Sharma

· started a discussion

· 1 Months ago

incorrect q (Question: 108542.0 )

here should be given that afer covering half distance, his bycycle broke down

Question:
I started on my bicycle at 7 a.m. to reach a certain place. After going a certain distance my bicycle went out of order. Consequently I rested for 35 minutes and came back to my house walking all the way. I reached my home at 1 p.m. If my cycling speed is 10 km/hr and my walking speed is 1 km/hr, then how much distance is  covered by me on my bicycle?
Options:
A) \(12\cfrac{3}{7}\) km
B) \(13\cfrac{4}{9}\) km
C) \(14\cfrac{3}{8}\) km
D) \(4\cfrac{61}{66}\) km
Solution:
Ans: (d)

Let the distance covered by bicycle be x km.


ANSHUL PRATAP SINGH

· commented

· 1 Months ago

D/10+D/1=5h25min now solve d=4 61/66

Arun

· commented

· 1 Months ago

Nope. He covered a particular distance in cycle first. When the cycle go broke down, he walked back the same distance to home.

So 'distance covered in cycle = distance covered by foot';
that means 'distance covered in cycle = 1/2 total distance traveled'.
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