Incomplete question (Question:361855.0)

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TRINA DAS

· started a discussion

· 1 Months ago

Incomplete question (Question:361855.0)

Give the figures in the question.

Question:

दी गई आकृति में, ABCD एक समचतुर्भुज है तथा BCE एक समद्विबाहु त्रिभुज है, जिसमे BC=CE, $∠ C B E$ = 84⁰ तथा $∠ A D C$ =78⁰ है तो $∠ D E C$ का मान (डिग्री में) क्या है?

Options:

Solution:

BC=CE

$\begin{matrix} ∠ C B E = 8 4^{0} = ∠ B E C \\ ∴ ∠ B C E = 18 0^{0} - 8 4^{0} - 8 4^{0} = 1 2^{0} \\ ∠ A D C = 7 8^{0} \\ ∴ D C B = 18 0^{0} - 7 8^{0} = 10 2^{0} \\ ∴ ∠ D C E = 10 2^{0} + 1 2^{0} = 11 4^{0} \end{matrix}$

DCE is an isosceles triangle

DC=CE

$\begin{matrix} ∴ ∠ C D E = ∠ D E C = θ \\ ∴ θ + θ + 114 = 180 \\ = > θ = 3 3^{0} = ∠ D E C \end{matrix}$

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Incomplete question (Question:361855.0)

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