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jishnu r

· started a discussion

· 1 Months ago

incomplete question (Question: 249103.0 )

how can we assume the ratio of deepak and pankaj u said only about the start give, u are often derive data out of thin air

Question:
In a 5 Km race, Hemant wins by 500 metres over Deepak, while Deepak can give a start of 200 metres to Pankaj in a 1 Km race. In a 5 Km race how much start can Hemant give Pankaj, so that both reach the destination simultaneously?
Options:
A) 1.2 Km 
B) 1.4 Km 
C) 1.6 Km 
D) 2 Km 
Solution:
Ans: (b)


Kumar

· commented

· 1 Months ago

500:4500 =10:9

Karthik Raju

· commented

· 1 Months ago

tupender ,,,,good idea

tupender morya

· commented

· 1 Months ago

or simply
5000 : 4500
and
1000 : 800

tupender morya

· commented

· 1 Months ago

5000-500=distance by deepak

500/4500 *100=(11 1/9)%=1/9 profit taken by hament on deepak for distance and for same time, it will be ratio of speed.
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