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Deepak kumar Singh

· started a discussion

· 1 Months ago

Wrong

Question:
If \(\cfrac{x}{\surd12}=\cfrac{2\sqrt{2}}{\sqrt{3}+\sqrt{2}}\)   then the value of x is?
Options:
A) 1
B) 4\((\surd18-\surd12)\)
C) -1
D) – 2
Solution:

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