CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
Suraj Kushwaha

· started a discussion

· 1 Months ago

I think there is a mistake in solution (Question: 108217.0 )

16x Ka 10%=1.6x hona chahiye

Question:

Cost of two watches are in the ratio 16 : 23. The cost of first watch increases by 10% and that of second by Rs.477. Now the cost of two watches is in the ratio 11 : 20. The price of the second watch (in Rs.) in the beginning was:

Options:
A) Rs.848
B) Rs.932
C) Rs.1219
D) Rs.1696
Solution:
Ans: (c)

Let the C.P. of first watch = 16x

C.P. of second watch = 23x

A.T.Q.,

\(\cfrac{16x\times1.1}{23x+477}=\cfrac{11}{20}\)

32x = 23x + 477

9x = 477

x = 53

Thus, the C.P. of second watch = 23 × 53 = \(\unicode{x20B9} \)1219 

Knowledge Expert

· commented

· 1 Months ago

Dear Student, Steo by step explanation is already given... As the ratio of two watches are given so CP of 1st watch = 16x and CP of 2nd watch = 23x 10% increase in x means 1.1*x so, 10% increase in 16x = 16x*1.1 23x is increase by 477 = 23x+477 Now the cost of two watches ratio = 11/20 so, (16x*1.1) / (23x+477) = 11/20 Calculate x now and find the value of 23x. Keep Learning with Us Best Wishes Team Toprankers

Deepak dubey

· commented

· 1 Months ago

16 x 100+10/100 Hoga when increase is given.

Mayank Singh

· commented

· 1 Months ago

best shortcut for this is only option C is divisible by 23
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions