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kesi

· started a discussion

· 1 Months ago

how to solve? (Question: 115296.0 )

there is error in in place of product there should be divide sign

Question:
\(\big[ 3 \sqrt[4] 2{\sqrt[3] {2^9}} \big]^4 \) \(\div\)  \(\\\ \big[ 6 \sqrt{3} \sqrt[3]{2^9} \big] ^ 4\)
Options:
A) \(\cfrac{1}{14}\)
B) \(\cfrac{1}{20}\)
C) \(\cfrac{1}{16}\)
D) \(\cfrac{1}{10}\)
Solution:
\(\big[ 3 \sqrt[4] 2{\sqrt[3] {2^9}} \big]^4 \) \(\div\)  \(\\\ \big[ 6 \sqrt{3} \sqrt[3]{2^9} \big] ^ 4\)

\(\big[3 (2(2^9)^{\frac{1}{3}}) ^{\frac{1}{4}} \big]^4\) \(\div\) \(\big[ 6 (3 (2^9)^{\frac{1}{3}})^{\frac{1}{2}}) \big]^4\)

\(\big[ 3 (2 (2)^3)^{\frac{1}{4}]} \big]^4\) \(\div\) \(\big[ 6 (3 (2^3)^{\frac{1}{2}})\big] ^4\)

\(\big[ 3 (2)^{\frac{4}{4}} \big]^4\)  \(\div\)  \(\big[ 3 × 2 × 3 ^{\frac{1}{2}} × 2 ^{\frac{3}{2}} \big]^ 4\)

[3 × 2]4 \(\div\)  [3 × 22]4

(6)4 \(\div\) (12)4

= \(\cfrac{1}{16}\) 

Rahul Ahuja

· commented

· 1 Months ago

then also answer is not coming bro...
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