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Anil

· started a discussion

· 1 Months ago

how PE=7? (Question: 115785.0 )

How do you get PE= 7?

Question:
In the adjoining figure, ACB is a right angled triangle. CD is the altitude. Circles are inscribed within the triangles ACD, BCD. P and Q are the centres of the circles. The distance PQ is (approx) :  

Options:
A) 5
B) \(\sqrt[]{50}\)
C) 7
D) 8
Solution:
Ans: (b)


Abhishek

· commented

· 1 Months ago

Incircle = Area/Semiperimeter

Shashank Shah

· commented

· 1 Months ago

Calculate in radius of two circles by using sides

Anil

· commented

· 1 Months ago

Is there any formula, or it is calculated using tangent from external point rule?
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