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PANKAJ SETH

· started a discussion

· 1 Months ago

how is angle OAC = angle OBA

Question:
Two circle C (O, r) and C´ (O´, r´) intersect at two points A and B and O lies on C (O´, r´). A tangent CD is drawn to the circle C' (O´, r´) at A. Then :

Options:
A) \(\angle \)OAC = \(\angle \)OAB
B) \(\angle \)OAB = \(\angle \)AO´ O
C) \(\angle \)AO´B = \(\angle \)CAB
D) None of these
Solution:
Ans: (a)


Knowledge Expert

· commented

· 1 Months ago

Dear student,
alternate segment theorem.
Keep learning,
Team TR

Sagar Sharma

· commented

· 1 Months ago

its a theorem alternate segment theorem

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