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naveen

· started a discussion

· 1 Months ago

Hh (Question: 111087.0 )

Why can't we put y=0 undecided equation

Question:

Consider the following system of inequalities :

5x +3y \(\geq\) 0 and y - 2x < 2

The solution of the above inequalities does not contain any part of the :

Options:
A) first quadrant
B) second quadrant
C) third quadrant
D) fourth quadrant
Solution:
Ans: (c)

5x + 3y > 0

x03
y0-5
y - 2x < 2
x01
y24

So, does not contain any part of third quadrant 

naveen

· commented

· 1 Months ago

In second equation
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