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Deepak

· started a discussion

· 1 Months ago

help (Question: 293462.0 )

koi short form main sol bata do plz plz

Question:

A, B and C start running simultaneous from X to Y. A reaches Y turns back and meet B at a distance of 11 km from Y. B reached Y, turns back and meet C at a distance of 9 km from Y. If the ratio of the speed of A and C is 3 : 2. What is the distance between X and Y ?

Options:
A)

99 km

B)

100 km

C)

120 km

D)

142 km

Solution:

Ans: (a)

  

Vijay Sharma

· commented

· 1 Months ago

bhai ye koi knowledge expert nahi hai ye alternate method maangne se kisi dusri site se answer chipka k neecha thanks...best wishes likh deta hai

Vijay Sharma

· commented

· 1 Months ago

ARE U A FOOL, HALF KNOWLEDGE EXPERT?

Just asking it because you are not answering any questions on other wrong/problematic questions.

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

We take the distance between X and Y = D

First case when A travel from X to Y and meet with D, A turn back thus distance travel by A is (d+11)
In case of B it is travel 11 km from its place if total distance is d, distance travel by B = (d-11).

Same method apply for case B and C both travel from B to C we get their distance respectively d+9 and d-9.
here Given ration A:C thus we put the A:B*B:C
See in the solution ,.,
After that we Comparing A:C = A:B*B:C.

we put the all values and solved it
we get a quadratic equation,
d^2-100d+99=0
we get two values 1 or 99.

Keep learning keep solving
Best wishes
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