CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
DS

· started a discussion

· 1 Months ago

hello gys........... (Question: 108829.0 )

what is the short trick

Question:

The cost price of two different types of watches is \(\unicode{x20B9} \)3600. On selling the first watch on 12% loss and second watch on 12% profit then there were no profit and no loss. What is the cost price of the first watch?

Options:
A) \(\unicode{x20B9} \)1680
B) \(\unicode{x20B9} \)2000
C) \(\unicode{x20B9} \)1800
D) \(\unicode{x20B9} \)2500
Solution:
Ans: (c) Let the CP of first watch be \(\unicode{x20B9} \)x.

\(\therefore\) The CP of second watch be \(\unicode{x20B9} \)3600 – x.

SP of first watch = \(\unicode{x20B9} \)0.88x

SP of second watch = \(\unicode{x20B9} \)1.12(3600 – x) 

A.T.Q.,

0.88x + 1.12(3600 – x) = 3600

\(\Rightarrow\) 0.88x – 1.12x = 3600 – 3600 × 1.12 

\(\Rightarrow\) 0.24x = 3600 × 0.12 \(\Rightarrow\) \(x=\unicode{x20B9} 1800 \)

Knowledge Expert

· commented

· 1 Months ago

Dear student,
There is no short trick.
Keep learning,
Team TR

Shivanshu Shukla

· commented

· 1 Months ago

12/100=12/100
1:1=2
2=3600
1800,1800
Cp1,çp2

Vimal Gautam

· commented

· 1 Months ago

Try With mixture and alligation method....1:1
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions