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AJAY KUMAR

· started a discussion

· 1 Months ago

Given explanation is not correct (Question: 332109.0 )

At steady state capacitor acts as a open circuit ( Ideal Voltage source) and Inductor acts as a short circuit (Ideal current source).

But in the question AC Source is also presented. At steady state DC Source effect is less.

Question:

The circuit shown in the figure given below, instantaneous current i(t) under steady state is given by

  

Options:
A)

zero

B)

5

C)

7.07sint

D)

7.07sin (t -  45O   )

Solution:

Ans:(a) At steady state: Inductor behave as a short circuit and capacitor behave as a open circuit.

i(t) = 0

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