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geeta soam

· started a discussion

· 1 Months ago

formula (Question:165060.0)

formula of (a-b)^3

Question:
If y = 98, then the value of [y (y² + 6y + 12) - 19] is
Options:
A) 999973
B) 999981
C) 999965
D) 999998
Solution:

Ans: (a) Let y = x – 2; where x = 100, substituting (x - 2) in place of y the required expression transforms as 

[(x – 2) ((x – 2)² + 6(x - 2) + 12) – 19]

= [(x - 2)³ + 6(x - 2)² + 12(x - 2) – 19]  ((a-b)³=a³ - b³ + 3ab (a-b))

= x³ - 27 

Required is the value of x³ - 27 when x = 100

= 999973 

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