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Narayana Rao Thorlikonda

· started a discussion

· 1 Months ago

Formula (Question: 108123.0 )

Elaborate the formula used in the solution

Question:
From any point inside an equilateral triangle, the lengths of perpendiculars on the sides are ‘a’ cm, ‘b’ cm and ‘c’ cms. Its area (in cm2) is:
Options:
A) \(\cfrac{\sqrt[]{2}}{3}\) (a + b + c)2
B) \(\cfrac{\sqrt[]{2}}{3}\) (a + b + c)
C) \(\cfrac{\sqrt[]{3}}{3}\) (a + b + c)2
D) \(\cfrac{\sqrt[]{3}}{3}\) (a + b + c)
Solution:
Ans: (c)

Let the side of the equilateral triangle be x cm.

Area of the equilateral triangle 


Knowledge Expert

· commented

· 1 Months ago

Dear Student
let centre be the point from where perpendiculars are dropped on the respective sides of the equilateral triangle of side a.
there will be 3 triangles
so, area
1/2a(x+y+z)=1/2ax+1/2ay+1/2az
by equating it with actual formulae for area.

mohit

· commented

· 1 Months ago

Bhai vo jo 3 triangle bnenge na , jaise bda triangle maan ke ABC
and o is the point where perpendicular on each sides meet. Then 3 triangles are
ABO ,BOC,COA and fir inka area nikaala perpenducular to x h ,,and base hmaare bde triangle ABC ki sides fir teeno triangle ka area add kardiya or bde triangle ABC ke equal rakh diya .
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