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Raj P Raj

· started a discussion

· 1 Months ago

formula is not clear (Question: 186072.0 )

formula is not clear

Question:
Each edge of a regular tetrahedron is 4 cm. Its volume (in cubic cm) is –
Options:
A) \(\cfrac{16 \sqrt{3}}{3}\) cm3
B) 16 \(\sqrt{3}\) cm3 
C) \(\cfrac{16 \sqrt{2}}{3}\) cm3
D) 16 \(\sqrt{2}\) cm3
Solution:
Ans: (c) 

volume  of the regular tetrahedron

= \({\sqrt{2} \over 12}\)a3 

= \(\frac{\sqrt{2}}{12}\) × 4 × 4 × 4cm3 

= \(\cfrac{16 \sqrt{2}}{3}\)  cm3 

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Volume of regular tetrahedron,

V=a^3 / 6 root 2

Put a = 4

You will get the same answer.

Hope you have a great learning with us!!

All the Best,
Team Toprankers

Talented Boy

· commented

· 1 Months ago

Yet to be approved!

Abhishek

· commented

· 1 Months ago

Actually it asking for height of regular tetrahedron.

Volume of Regular tetrahedron= a^3/16^0.5

Height of regular tetrahedron = (2/3) x a x volume of tetrahedron
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