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ROLLY KUMAR

· started a discussion

· 1 Months ago

f (Question: 99450.0 )

bhai kisne banaya hai ye question, naam to bata de

Question:
A cow is tied to one corner of a closed shed located in a field. The length and width of the shed are 15 m × 15 m and the length of the rope that is used to tie the cow is 25 m. What is the area in which the cow can graze?
Options:
A) \(478.75π sq. m\)
B) \(542.25 π sq. m\)
C) \(518.75π sq. m\)
D) \(604.25 π sq. m\)
Solution:
Ans: (c)



The area that can be grazed by the cow is the sum of the areas of the regions A, B, C. 
∴ Total area that can be grazed
\(=\cfrac{270}{360}× π(25)^2 + 2\left ( \cfrac {90}{360}×π(10)^2 \right )=\cfrac{π}{4}(3 × 625 + 2 × 100)\)
\(=\cfrac{2075π}{4}= 518.75 π\)

Knowledge Expert

· commented

· 1 Months ago

Dear student
The name of the creator cannot be revealed due to privacy and security purposes
By the way, the solution is literally clear
The length of the rope being 25 m
The cow grazes 270degrees and 2 turns around 90degress
that gives us
270/360*pi(25)^2+2*[90/360*(10)^2]
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