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amir

· started a discussion

· 1 Months ago

explanation (Question: 198326.0 )

which formula using to solve this question?

Question:

What was the day on 10th May 1857.

Options:
A)

Monday

B)

Sunday

C)

Tuesday

D)

Friday

Solution:

Ans: (b)

Knowledge Expert

· commented

· 1 Months ago

Important Points:

An ordinary year has 365 days = 52 weeks and 1 odd day.

A leap year has 366 days = 52 weeks and 2 odd days.

Century = 76 Ordinary years + 24 Leap years.

Century contain 5 odd days.

200 years contain 3 odd days.

300 years contain 1 odd day.

400 years contain 0 odd days.

Last day of a century cannot be Tuesday, Thursday or Saturday.

First day of a century must be Monday, Tuesday, Thursday or Saturday.

Suppose Q is: What was the day of the week on 28th May, 2006?

Explanation:

Leave 1600,400
it's odd day is zero
----

5=(5/4)leap yr+[5-1]ordinary day
=1 leap year+4 ordinary day
=1*2+4
=6 odd day
---------

Jan Feb Mar Apr May
31 28 31 30 28 ->total->148days->21weeks+1odd day
->1 odd day

Total=0+0+6+1
=7 odd day

Sun Mon Tue Wed Thu Fri Sat
0 1 2 3 4 5 6
7

Day is Sunday.

Garg Pawan

· commented

· 1 Months ago

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