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neeta

· started a discussion

· 1 Months ago

explain second line of the solution (Question: 326290.0 )

how QRP=QSR ??

Question:

In the given figure, PT is the tangent of a circle with centre O at point R. If diameter SQ is increased, it meets with PT at point P. If ∠SPR = xo and ∠QSR = yo. What is the value of xo + 2yo?

  

Options:
A)

90º

B)

105º

C)

135º

D)

180º

Solution:

Ans: (a)


vishal kanaujia

· commented

· 1 Months ago

Alternate segment theorem
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