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Dilesh kumar gupta

· started a discussion

· 1 Months ago

Pls explain

Question:

Three currents i1, i2 and i3 are approaching a node. If i1 = 10 sin (400 t + 60°) A, and i2 = 10 sin (400 t – 60°)A, then i3 is

Options:
A)

0 A

B)

10 (sin 400 t) A

C)

–10 (sin 400 t)A

D)

53     (3 sin 400 t)A

Solution:

Ans: (c)

Pawan Agrawal JI

· commented

· 1 Months ago

this que. is based in PSOC symmetrical componant

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