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Knowledge Expert
· commented
· 1 Months ago
Solve as below,
Cos 10 cos 30 cos 50 cos 70 = cos 30 ( cos 10 cos 50) cos 70
root 3 / 2 * 1/2(2cos 10 cos 50) cos 70
root 3/4* (cos60 +cos 40) cos70 [ 2cosx cosy = cos(x+y) + cos(x-y)]
root 3/4 * ( cos60 cos 70 + cos40 cos 70)
use same identity again
.
.
.
you will get = root 3/8 * root 3/2 = 3/16
Thanks and Regards
Team TR