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bhanu kushwaha

· started a discussion

· 1 Months ago

Explain please (Question: 111097.0 )

Any explain this in detail

Question:
ABCD is a square whose side is a. If AB and AD be the co-ordinate axes, then the equation of the circumcircle is:
Options:
A) x2+y2+2a(x+y)=0
B) x2 + y2 + a (x+y) =0
C) x2+y2 - a (x+y)  = 0
D) x2+y2 - a (x - y) = 0
Solution:
Ans: (c)


Let the side be 'a'

It start from origin A (0, 0)

B = Y axis = (0, a)

D = X axis = (a, 0)

C = (a, a)

Since AC is diameter

We will use the diametric form of circle

(x – x1) (x – x2) + (y – y1) (y – y2) = 0

(x – 0) (x – a) + (y – 0) (y – a) = 0

x (x – a) + y (y – a) = 0

x2 – ax + y2 – ay = 0

x2 + y2 – a (x + y) = 0

Knowledge Expert

· commented

· 1 Months ago

Dear student
We resolved it

Best wishes
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