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vivek

· started a discussion

· 1 Months ago

this method is very time consuming must provide short trick or short explanation

Question:

P and Q are two points observed from the top of a building 20\(\sqrt{3}\) m high. If the angles of the points are complementary and PQ = 40 m, then the distance of P from the building is–

Options:
A) 10 m
B) 20 m
C) 15 m
D) 25 m
Solution:
Ans: (b)


PB(40 + PB) = 1200

PB2 + 40PB – 1200 = 0

PB2 + 60PB – 20PB – 1200 = 0

PB(PB – 60) – 20(PB + 600) = 0

(PB – 20) (PB + 60) = 0

So, PB = 20 m

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