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kunal

· started a discussion

· 1 Months ago

error (Question: 300424.0 )

pls check the question before giving solution

Question:

The length, breadth and height of a cubiod are in the ratio 1 : 2 : 3. The length, breadth and height of cuboid are increased by 200%, 300% and 400% respectively. Then in surface area of cuboid is:-

Options:
A)

1620.20%

B)

1618.18%

C)

1600.09%

D)

1679.80%

Solution:

Ans: (b)

Initial total surface area ⇒

⇒ 2[Lb+bH+HL]

⇒ [x ×2x+2x×3x+3x×x]

= 22 x2

After increased ⇒ 2 [3x×8x+8x×15x+15x×3x]

⇒ 2[24x2 + 120x2+45x2]

⇒ 378 x2

Increased area ⇒ 378x2 – 22x2 = 356x2

Increased % ⇒ \(\cfrac{356x^2}{22x^2}\) × 100

⇒ 1618.18%

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