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saurabh kaushal

· started a discussion

· 1 Months ago

question wrong
bhaang kha k que daalte ho kya

Question:

If (\(x + \frac{1}{x})^2\)   = 3, then find x206 + x200 + x90 + x84 + x18 + x12 + x6 + 1

Options:
A)

67

B)

0

C)

5

D)

8

Solution:

Ans: (b)

  

Sohil Rajput

· commented

· 1 Months ago

@CHATA PAD JAEGA

saurabh kaushal

· commented

· 1 Months ago

@Sohil Rajput question galat tha pehle sahi kiya h toprankers ne
isliye que lagaane pe dhyaan do comment kr k hero na bano

Sohil Rajput

· commented

· 1 Months ago

sahi hain question ekdum sahi se padh

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