Emphasise (Question:579224.0)

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TRINA DAS

· started a discussion

· 1 Months ago

Emphasise (Question:579224.0)

Please give the solution in more detail.

Question:

In a triangle ABC the internal bisector of angle A meets BC at D. If AB = 4 cm, AC = 3 cm and ∠A = 60^o then the length of AD is-

Options:

2 cm

$\frac{12 \sqrt{3}}{7} c m$

$15 \sqrt{\frac{3}{8}} c m$

$6 \sqrt{\frac{3}{7}} c m$

Solution:

Ans: (b)

$A D = \frac{2 . A B . A C}{A B + A C} s i n 60$

= $\frac{12 \sqrt{3}}{7}$

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Emphasise (Question:579224.0)

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