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Pranay SB

· started a discussion

· 1 Months ago

Else do this: (Question: 271963.0 )

Take a right angle triangle for which pythagorus theorem is valid.

I'm taking p=3; q=4; Therefore r=5;

*Substitute the above values in the first option: radius is=1 (which is less than the sides of the triangle, hence valid)
* In all other options you will get radius>the values of sides which is impossible.
So we should go with option 1.
Hope this helps

Question:

Let p, q and r are sides of right angle triangle, where r is the hypotenuse. The radius of the circle which touches the sides of the triangle is –

Options:
A)

(p+q-r)2    

B)

(p+q+r)2    

C)

(p+2q+2r)2    

D)

(2p+2q-r)2    

Solution:

Ans: (a)

  

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