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Deep Das

· started a discussion

· 1 Months ago

please give any other shortcut to solve this type of problem

Question:
A, B and C complete a work in 10, 12 and 15 days respectively. They started the work together. But A left the work before 5 days of its completion. B also left the work 2 days after A left. In how many days will the work completed ? 
Options:
A) 4 days 
B) 5 days 
C) 7 days 
D) 8 days 
Solution:
Ans: (c)


If A work 5 days more than total units of work = 60 + 5 × 6 = 90 units

If B work 3 days more than total units of work = 90 + 3 × 5 = 105 units

So, time required to complete the work = \(\cfrac{105}{15}\)  = 7 days.

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