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Ravindra singh rathore

· started a discussion

· 1 Months ago

Put n=0. Use formula CosA.CosB+SinA.SinB=Cos(a-B)

Question:

The value of sin(n + 1) θ    . sin(n + 2)  θ    + cos(n + 1)  θ     . cos(n + 2)  θ    is equal to:-

Options:
A)

sin  θ   

B)

cos  θ   

C)

– cos  θ   

D)

sin2  θ   

Solution:

Ans: (b)

  

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