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MAHAVEER PRASAD

· started a discussion

· 1 Months ago

easy approach (Question: 275789.0 )

bc-c+1=0 & ac-a+1=0
b=(c-1)/c
b=1-1/c .........(i)
c=(a-1)/a..........(ii)
put value of c from eq (ii) to in eq (i)
b=1-a/(a-1)
b= -1/(a-1) or 1/(1-a)
so, 1/b = (1-a) Ans.

Question:

If (bc – c + 1) = 0 and (ac – a + 1) = 0 then  1b    = ?

Options:
A)

a + 1

B)

a – 1

C)

1 – a

D)

11-a    

Solution:

Ans: (c)

  

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