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Dhananjay Dks Dks

· started a discussion

· 1 Months ago

Ds Singh (Question:107654.0)

It's not work for other question,pls solve this another way

Question:
The length of three medians of a triangle are 9 cm, 12 cm and 15 cm. The area (in sq. cm) of the triangle is:
Options:
A) 48
B) 144
C) 24
D) 72
Solution:
Ans: (d) Area of triangle = \(\cfrac{4}{3}\times\) Area of triangle formed by taking median as a side of triangle

  A= 9, B=12, C=15

  Side = \(\cfrac{A+B+C}{2}\) = \(\cfrac{9+12+15}{2} \)  = 18

   area of triangle =\(\frac{4}{3}\) \(\sqrt[]{S(S-a)(S-b)(S-c)}\)

 \(\cfrac{4}{3}\sqrt[]{18\times 9\times 6\times 3}\)

\(= \cfrac{4}{3}\times9 \times 3 \times 2=72\)

Knowledge Expert

· commented

· 1 Months ago

Dear student
This approach is work only for Right triangle.

Best wishes
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